Sort Array By Parity
Problem Statement
Given an integer array nums
, move all the even integers at the beginning of the array followed by all the odd integers.
Return any array that satisfies this condition.
Example 1:
Input: nums = [3,1,2,4]
Output: [2,4,3,1]
Explanation: The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.
Example 2:
Input: nums = [0]
Output: [0]
Constraints:
1 <= nums.length <= 5000
0 <= nums[i] <= 5000
Code
Python
class Solution:
def sortArrayByParity(self, nums: List[int]) -> List[int]:
a=[]
for i in nums:
if i%2==0:
a.insert(0,i)
else:
a.append(i)
return a