Random Pick with Weight
Problem Statement
You are given a 0-indexed array of positive integers w
where w[i]
describes the weight of the i
th index.
You need to implement the function pickIndex()
, which randomly picks an index in the range [0, w.length - 1]
(inclusive) and returns it. The probability of picking an index i
is w[i] / sum(w)
.
For example, if w = [1, 3]
, the probability of picking index 0
is 1 / (1 + 3) = 0.25
(i.e., 25%
), and the probability of picking index 1
is 3 / (1 + 3) = 0.75
(i.e., 75%
).
Example 1:
Input
["Solution","pickIndex"]
[[[1]],[]]
Output
[null,0]
Explanation
Solution solution = new Solution([1]);
solution.pickIndex(); // return 0. The only option is to return 0 since there is only one element in w.
Example 2:
Input
["Solution","pickIndex","pickIndex","pickIndex","pickIndex","pickIndex"]
[[[1,3]],[],[],[],[],[]]
Output
[null,1,1,1,1,0]
Explanation
Solution solution = new Solution([1, 3]);
solution.pickIndex(); // return 1. It is returning the second element (index = 1) that has a probability of 3/4.
solution.pickIndex(); // return 1
solution.pickIndex(); // return 1
solution.pickIndex(); // return 1
solution.pickIndex(); // return 0. It is returning the first element (index = 0) that has a probability of 1/4.
Since this is a randomization problem, multiple answers are allowed.
All of the following outputs can be considered correct:
[null,1,1,1,1,0]
[null,1,1,1,1,1]
[null,1,1,1,0,0]
[null,1,1,1,0,1]
[null,1,0,1,0,0]
......
and so on.
Constraints:
1 <= w.length <= 10
41 <= w[i] <= 10
5pickIndex
will be called at most10
4 times.
Code
Python Code
import random
class Solution:
def __init__(self, w):
"""
:type w: List[int]
"""
self.w = w
self.n = len(w)
for i in range(1,self.n):
w[i] += w[i-1]
self.s = self.w[-1]
def pickIndex(self):
"""
:rtype: int
"""
seed = random.randint(1,self.s)
l,r = 0, self.n-1
while l<r:
mid = (l+r)//2
if seed <= self.w[mid]:
r = mid
else:
l = mid+1
return l