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Sudoku Solver

Problem Statement

Write a program to solve a Sudoku puzzle by filling the empty cells.

A sudoku solution must satisfy all of the following rules:

Each of the digits 1-9 must occur exactly once in each row. Each of the digits 1-9 must occur exactly once in each column. Each of the digits 1-9 must occur exactly once in each of the 9 3x3 sub-boxes of the grid. The '.' character indicates empty cells.

Leetcode Link

Example 1:

Input: board = [["5","3",".",".","7",".",".",".","."],["6",".",".","1","9","5",".",".","."],[".","9","8",".",".",".",".","6","."],["8",".",".",".","6",".",".",".","3"],["4",".",".","8",".","3",".",".","1"],["7",".",".",".","2",".",".",".","6"],[".","6",".",".",".",".","2","8","."],[".",".",".","4","1","9",".",".","5"],[".",".",".",".","8",".",".","7","9"]]
Output: [["5","3","4","6","7","8","9","1","2"],["6","7","2","1","9","5","3","4","8"],["1","9","8","3","4","2","5","6","7"],["8","5","9","7","6","1","4","2","3"],["4","2","6","8","5","3","7","9","1"],["7","1","3","9","2","4","8","5","6"],["9","6","1","5","3","7","2","8","4"],["2","8","7","4","1","9","6","3","5"],["3","4","5","2","8","6","1","7","9"]]


Constraints:

  • board.length == 9
  • board[i].length == 9
  • board[i][j] is a digit or '.'.
  • It is guaranteed that the input board has only one solution.

Code

Python Code

class Solution:
def solveSudoku(self, board: List[List[str]]) -> None:
"""
Do not return anything, modify board in-place instead.
"""
assert(self.backtrack(board, 0, 0))
return

def backtrack(self, board: List[List[str]], r: int, c: int) -> bool:
# Go to next empty space
while board[r][c] != '.':
c += 1
if c == 9: c, r = 0, r+1
if r == 9: return True
# Try all options, backtracking if not work
for k in range(1, 10):
if self.isValidSudokuMove(board, r, c, str(k)):
board[r][c] = str(k)
if self.backtrack(board, r, c):
return True
board[r][c] = '.'
return False

def isValidSudokuMove(self, board: List[List[str]], r: int, c: int, cand: int) -> bool:
# Check row
if any(board[r][j] == cand for j in range(9)): return False
# Check col
if any(board[i][c] == cand for i in range(9)): return False
# Check block
br, bc = 3*(r//3), 3*(c//3)
if any(board[i][j] == cand for i in range(br, br+3) for j in range(bc, bc+3)): return False
return True