Copy List with Random Pointer
Problem Statement
A linked list of length n
is given such that each node contains an additional random pointer, which could point to any node in the list, or null
.
Construct a deep copy of the list. The deep copy should consist of exactly n
brand new nodes, where each new node has its value set to the value of its corresponding original node. Both the next
and random
pointer of the new nodes should point to new nodes in the copied list such that the pointers in the original list and copied list represent the same list state. None of the pointers in the new list should point to nodes in the original list.
For example, if there are two nodes X
and Y
in the original list, where X.random --> Y
, then for the corresponding two nodes x
and y
in the copied list, x.random --> y
.
Return the head of the copied linked list.
The linked list is represented in the input/output as a list of n
nodes. Each node is represented as a pair of [val, random_index]
where:
val
: an integer representingNode.val
random_index
: the index of the node (range from0
ton-1
) that therandom
pointer points to, ornull
if it does not point to any node. Your code will only be given thehead
of the original linked list.
Example 1:
Input: head = [[7,null],[13,0],[11,4],[10,2],[1,0]]
Output: [[7,null],[13,0],[11,4],[10,2],[1,0]]
Example 2:
Input: head = [[1,1],[2,1]]
Output: [[1,1],[2,1]]
Example 3:
Input: head = [[3,null],[3,0],[3,null]]
Output: [[3,null],[3,0],[3,null]]
Example 3:
Input: head = []
Output: []
The given linked list is empty (null pointer), so return null.
Constraints:
0 <= n <= 1000
- -104 <= Node.val <= 104
Node.random
isnull
or is pointing to some node in the linked list.
Implementation
We will be using two passes method, where in the first pass we make copy of the nodes and store it in hashmap. In second pass we link them. We use two passes as this cannot be done in single pass because there might be a case where we have to link the node which isn't created yet while copying.
- Space Complexity:
O(n)
- Time Complexity:
O(n)
Code
"""
# Definition for a Node.
class linkedListNode:
def __init__(self, value: int, nextNode: 'linkedListNode' = None, random: 'linkedListNode' = None):
self.value = value
self.nextNode = nextNode
"""
class Solution:
def copyRandomList(self, head: 'linkedListNode'):
if head is None:
return head
# when the element has to point null
hashmap = {None: None}
curr = head
# copy the nodes to hashmap
while curr != None:
newNode = linkedListNode(curr.value + '@')
hashmap[curr] = newNode
curr = curr.nextNode
curr = head
# link the nodes
while curr != None:
newNode = hashmap[curr]
newNode.nextNode = hashmap[curr.nextNode]
newNode.random = hashmap[curr.random]
curr = curr.nextNode
return hashmap[head]